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Question

What must be subtracted from x4+2x313x212x+21 so that the result is exactly divisible by x24x+3?

A
2x
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B
3
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C
3x
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D
2x3
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Solution

The correct option is C 2x3
Given: f(x)=x4+2x313x212x+21
g(x)=x24x+3
By division algorithm
f(x)=q(x)×g(x)+r(x)
g(x)=f(x)r(x)q(x)
So. r(x) must be subtracted so, that result is exactly divisible by x24x+3.
2x3 must be subtracted from f (x), so that result is exactly divisible by x24x+3.
396372_313259_ans_95278f104e0d425b981527e20a68396b.png

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