What must be subtracted from x4+2x3−13x2−12x+21 so that the result is exactly divisible by x2−4x+3?
A
2x
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B
3
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C
3x
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D
2x−3
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Solution
The correct option is C2x−3 Given: f(x)=x4+2x3−13x2−12x+21 g(x)=x2−4x+3 By division algorithm f(x)=q(x)×g(x)+r(x) g(x)=f(x)−r(x)q(x) So. r(x) must be subtracted so, that result is exactly divisible by x2−4x+3. 2x−3 must be subtracted from f (x), so that result is exactly divisible by x2−4x+3.