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Ostwald Dilution Law Mathematical Interpretation

What

Question

What % of the carbon in the $H_{2} C O_{3} - H C O_{3}^{-}$ buffer should be in the form of $H C O_{3}^{-}$ so as to have a neutral solution? $(K_{a} = 4 \times 10^{- 7})$

20 %

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40 %6

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60 %

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80 %

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Solution

The correct option is C 60 %
C. 60%
$p H = p K_{a} + l o g \frac{B a s e}{A c i d} (p K_{a} = - l o g K_{a} = - l o g 4 \times 10^{- 7} = 6.4) 7 = 6.4 + l o g \frac{B a s e}{a c i d} l o g B / A = 0.6$

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Similar questions

H_{2} C O_{3}, H C O_{3}^{-}

H C O_{3}^{-}

(K_{a} = 4 \times 10^{- 7})

An aqueous solution of carbonic acid ( $H_{2} C O_{3}$ ) contains

(H_{2} C O_{3})

K_{a_{1}} = 4.0 \times 10^{- 7}

K_{a_{2}} = 7.0 \times 10^{- 11}

[H C O_{3}^{-}]

0.025 M

C O_{2}

C O_{2}

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