What product is formed in the acid-catalyzed reaction between methanol( $C H_{3} - O H$ ) and
propene ( $C H_{2} = C H - C H_{3}$ ).

H O - C (C H_{3})_{3}

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C H_{3} - C H_{2} - C H_{2} - O - C H_{3}

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C H_{3} - C H_{2} - C H_{2} - C H_{2} - O H

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(C H_{3})_{2} C H (O C H_{3})

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Solution

The correct option is D $(C H_{3})_{2} C H (O C H_{3})$
$Therefore Option (d) is the correct option.$

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Similar questions

The reaction of propene with HOCl $(C l_{2} + H_{2} O)$ proceeds through the intermediate:

C H_{3} - C H_{2} - O H | C H - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} | C H - C H_{3}

C H_{3} - C H_{2} - O H | C H - C H_{2} - C H_{2} - C | H C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{2} - C H_{2} - O H

C H_{3} - C H_{2} - C | C H_{3} H - O H

C H_{3} - C H_{2} - C H_{3} | C | C H_{3} - O H

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