What quantity must be added to each term of the ratio $8 ∶ 15$ so that it becomes equal to $3 ∶ 5$ ?

2 \frac{1}{2}

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1 \frac{1}{4}

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2

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3

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Solution

The correct option is A $2 \frac{1}{2}$
Let $x$ be added to each term of the ratio $8 ∶ 15$ .
Given: $\frac{(8 + x)}{(15 + x)} = \frac{3}{5}$
$\Rightarrow 40 + 5 x = 45 + 3 x$
$\Rightarrow x = 2 \frac{1}{2}$

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