Question

What should be added to $\frac{-7}{8}$ to get $\frac{5}{9}$?

Answer 1

$\begin{array}{l}\mathrm{Let}\mathrm{the}\mathrm{other}\mathrm{number}\mathrm{be}x.\\ x+\left(\frac{-7}{8}\right)=\frac{5}{9}\\ \text{=>x =}\frac{5}{9}-\left(\frac{-7}{8}\right)\\ \begin{array}{l}=\frac{5}{9}+\frac{7}{8}\\ \mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}9\mathrm{and}8\mathrm{is}72.\\ \begin{array}{l}=\frac{40+63}{72}\\ =\frac{103}{72}\end{array}\end{array}\end{array}$

Hence , the other number is $\frac{103}{72}$