Question

What should be added to $\frac{-7}{8}$ to get $\frac{4}{9}$?

• A. $\frac{72}{95}$
• B. $\frac{95}{72}$
• C. $\frac{-72}{95}$
• D. $\frac{-95}{72}$

Answer 1

The correct option is B $\frac{95}{72}$

Let the number to be added be x.
Then, $\frac{-7}{8}+x=\frac{4}{9}\Rightarrow x=\frac{4}{9}-\left(\frac{-7}{8}\right)=\frac{4}{9}+\frac{7}{8}[Since-\left(\frac{-7}{8}\right)=\frac{7}{8}]=\frac{(32+63)}{72}=\frac{95}{72}$
Hence, the required number is $\frac{95}{72}$.