Question

What should be added to $x^2+3x-8$ to get $x^2+x+6$?

• A. 3$x^2$ - 8
• B. - 2$x$ + 14
• C. $x$ + 6
• D. 2$x$ + 14

Answer 1

The correct option is B

- 2$x$ + 14

Here we have to subtract
($x^2$ + 3$x$ - 8) from ($x^2$ + $x$ + 6),
So, we have to find the solution of
($x^2$ + $x$ + 6) - ($x^2$ + 3$x$ - 8).

$(x^2+x+6)$
$-(x^2+3x-8)$
$\underset{–}{(-)(-)(+)}$
$0x^2-2x+14$

So, (- 2$x$ + 14) should be added to ($x^2$ + 3$x$ - 8) to get ($x^2$ + $x$ + 6).