Question

What should be the degree of hydrolysis of 0.01M ammonium acetate solution at ${25}^{o}C$, if $K_h=3.175\times {10}^{-5}$ :

• A. $5.63\times {10}^{-3}$
• B. $5.63\times {10}^{-4}$
• C. $5.63\times {10}^{-2}$
• D. $5.63\times {10}^{-1}$

Answer 1

The correct option is D $5.63\times {10}^{-1}$

Now $k_h=c{h}^2$

When h=degree of hydrolysis.

$\therefore h=\sqrt{\frac{K_h}{c}}=\sqrt{\frac{3.175\times {10}^{-5}}{{10}^{-2}}}$

$=\sqrt{3.175\times {10}^{-3}}$

$h=\sqrt{31.75}\times {10}^{-2}=5.63\times {10}^{-2}$