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Question

What should be the value of Kc for the reaction 2SO2(g)+O2(g)2SO3(g), if the amount are SO3=48g,SO2=12.8g and O2=9.6g at equilibrium and the volume of the container is one litre?

A
64
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B
30
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C
42
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D
8.5
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Solution

The correct option is C 30
2SO2(g)+O2(g)2SO3(g)

We know, KC=[SO3]2[SO2]2[O2]

Given, SO3=48g,SO2=12.8g,O2=9.6g at equilibrium concentration =molesV (in lit),
Given volume =1 lit

moles of SO3=weightmoleculesweight=4880=0.6

moles of SO2=12.864=0.2

moles of O2=9.632=0.3

moles = concentration ( volume 1 lit)

KC=(0.6)2(0.3)(0.2)2=30

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