What should be the value of Kc for the reaction 2SO2(g)+O2(g)⇌2SO3(g), if the amount are SO3=48g,SO2=12.8g and O2=9.6g at equilibrium and the volume of the container is one litre?
A
64
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B
30
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C
42
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D
8.5
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Solution
The correct option is C 30 2SO2(g)+O2(g)⇌2SO3(g)
We know, KC=[SO3]2[SO2]2[O2]
Given, SO3=48g,SO2=12.8g,O2=9.6g at equilibrium concentration =molesV(inlit),