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Question

What should be the value of Kc for the reaction 2SO2(g)+O2(g)2SO3(g), if the amount are SO3=48g, SO2=12.8g and O2=9.6g at equilibrium and the volume of the container is one litre?

A
64
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B
2.7
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C
30
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D
8.5
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Solution

The correct option is A 30
2SO2+O22SO3(g)
Keq or KC=[SO3]2[SO2]2[O2]
Number of moles of SO2 at equilibrium= 12.864=0.2
Number of moles of SO3 at equilibrium= 4880=0.6
Number of moles of O2 at equilibrium= 9.632=0.3
As volume is 1L
So, number of moles= concentration
KC=[0.6]2[0.2]2[0.3]=30 .

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