What should be the volume of the milk (in $m^{3}$ ) which measures 5 L?

5 \times 10^{- 3} m^{3}

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5 \times 10^{3} m^{3}

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5 \times 1000 m^{3}

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5 \times 10^{6} m^{3}

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Solution

The correct option is D $5 \times 10^{- 3} m^{3}$
$1 L = 10^{- 3} m^{3}$
Since 1 L = 1000 $c m^{3}$ and 1 m = 100 cm
$\frac{1 m}{100 c m} = 1 = \frac{100 c m}{1 m}, o r (\frac{1 m}{100 c m})^{3} = \frac{1 m^{3}}{10^{6} c m^{3}}$ = $1^{3}$ = 1
Therefore $5 L = 5 \times 10^{- 3} m^{3}$
option A is correct

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What should be the volume of the milk (in m3) which measures 5 L?

The correct option is D 5×10−3m31 L=10−3 m3Since 1 L = 1000 cm3 and 1 m = 100 cm1m100cm=1=100cm1m,or(1m100cm)3=1m3106cm3 = 13 = 1Therefore 5 L=5×10−3 m3option A is correct

What should be the volume of the milk (in $m^{3}$ ) which measures 5 L?