What values of x satisfy the given equation x2-3 x-10-0 -A- -2 and -6B- 5 and -2C- 7 and 6D- 10 and 5

The correct option is B 5 and nbsp; 2 Given, x^2 3x 10 = 0 nbsp; Values satisfying the equation are roots. nbsp;x^2 5x +2x 10 = 0 (x 5) (x +2) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

What values o...

Question

What values of $x$ satisfy the given equation
$x^{2} - 3 x - 10 = 0$ ?

-2 and -6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 and 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 and -2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 and 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
5 and -2

Given, $x^{2} - 3 x - 10 = 0$

Values satisfying the equation are roots.
$x^{2} - 5 x + 2 x - 10 = 0 (x - 5) (x + 2) = 0 x = 5 & - 2$

The values satisfying the equation are $5$ and $- 2$

Suggest Corrections

Similar questions

What values of $x$ satisfy the given equation
$x^{2} - 3 x - 10 = 0$ ?

Solve for x

$x^{2}$ - 3x - 10 = 0

Find the equation of circle circumscribing the quadrilateral formed by four lines $3 x + 4 y - 5 = 0$ , $4 x - 3 y - 5 = 0$ , $3 x + 4 y + 5 = 0$ and $4 x - 3 y + 5 = 0$

Q. The root of a quadratic equation are 5 and −2. Then, the equation is
(a)

x^{2} - 3 x + 10 = 0

(b)

x^{2} - 3 x - 10 = 0

(c)

x^{2} + 3 x - 10 = 0

(d)

x^{2} + 3 x + 10 = 0

Q. What are the possible values of x, satisfying the equation

| 4 x + 6 | + 2 = 2 x + 3

Join BYJU'S Learning Program

What values of x satisfy the given equation x2−3x−10=0 ?

The correct option is C 5 and -2 Given, x2−3x−10=0 Values satisfying the equation are roots. x2−5x+2x−10=0(x−5)(x+2)=0x=5 & −2 The values satisfying the equation are 5 and −2

What values of $x$ satisfy the given equation
$x^{2} - 3 x - 10 = 0$ ?

The correct option is C
5 and -2

Given, $x^{2} - 3 x - 10 = 0$

Values satisfying the equation are roots.
$x^{2} - 5 x + 2 x - 10 = 0 (x - 5) (x + 2) = 0 x = 5 & - 2$

The values satisfying the equation are $5$ and $- 2$