What volume does 8.5 g ${N H}_{3}$ occupy at STP?

2.8

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5.6

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11.2

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22.4

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44.8

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Solution

The correct option is B $11.2$ L
The molecular weight of $N H_{3}$ is 17 g/mol.
8.5 g $N H_{3} = \frac{8.5}{17} = 0.5$ moles.
At STP, 1 mole of any gas occupies a volume of 22.4 L.
Hence, at STP, 0.5 mole of $N H_{3}$ gas occupies a volume of $0.5 \times 22.4 = 11.2$ L.

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