Question

What volume of 6N and 2N HCl should be mixed to get 100mL of 5N solution?

Answer 1

Let x = Liters of 6 N HCl and let y = Liters of 2 N HCl

x + y = 0.100 L
6 x + 2 y / 0.100 = 5

x = 0.100 - y
6 ( 0.100 - y ) + 2y = 0.5

x = 0.100 - y
0.600 - 6 y + 2y = 0.5

x = 0.100 - y
4 y = 0.1


x = 0.100 - y
y = 0.025 L of 2 N HCl => 25 mL

x = 0.100 - 0.025 = 0.075 L of HCl 6 N => 75 mL