What volume of air containing $21$ % of oxygen by volume is required to completely burn one kg of carbon that contains $15$ % of non-combustible substance?

7555L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1586.6L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

850L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5745.5L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
7555L

Combustible part out of $1 k g$ = $850 g m$

$850 g$ of carbon= $70.83 m o l e s$
1 mole of C requieres one mole of oxygen for complete combustion:
$C + O_{2} \to C O_{2}$

Vol. of oxygen needed for $70.83 m o l e$ of carbon = $70.83 \times 22.4 = 1586.6 L$

$∴$ Vol. of air that can supply $1586.6 L$ of oxygen = $\frac{1586.6 \times 100}{21}$ = $7555.5 L$

Suggest Corrections

Similar questions

What volume of air containing $21$ % of oxygen by volume is required to completely burn one kg of carbon that contains $15$ % of non-combustible substance?

Q. What volume of air containing 21% oxygen by volume is required to completely burn 1 kg of carbon containing 100% combustible substances ?

What volume of 21% oxygen by volume is required of air at NTP to completely burn 1000 gram of sulphur containing 4% incombustible matter ?

Q. Air contains

21 %

of oxygen by volume. Calculate the volume of such air required for the complete combustion of

700 c m^{3}

of ethylene

(C_{2} H_{4})

15^{\circ} C

and

756 m m

pressure.

Join BYJU'S Learning Program

What volume of air containing 21% of oxygen by volume is required to completely burn one kg of carbon that contains 15% of non-combustible substance?

What volume of air containing $21$ % of oxygen by volume is required to completely burn one kg of carbon that contains $15$ % of non-combustible substance?