What volume of Butane is burnt for every $1000 c m^{3}$ of air used in the reaction under the same conditions.

$50 c m^{3}$

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$30.7 c m^{3}$

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$45 c m^{3}$

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$90 c m^{3}$

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Solution

The correct option is B
$30.7 c m^{3}$

$2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O$

Volume of $O_{2}$ in $1000 c m^{3}$ of air = 20%

$= \frac{20}{100} \times 1000 = 200 c m^{3}$

$2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O$

2 Vol $\to$ 13 Vol

$∴$ Volume of butane burnt $= \frac{200 \times 2}{13}$

$= \frac{400}{13}$

$= 30.7 c m^{3}$

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Similar questions

What volume of propane is burnt for every $500 c m^{3}$ of air used in the reaction under the same conditions?
(Assuming oxygen is $(\frac{1}{5})^{t h}$ of air)

$C_{3} H_{8} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O$

Q. If

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litres of butane is completely burnt the volume of

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Q. Propane burns in air according to the following equation:

C_{3} H_{8} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O

.
What volume of propane is consumed on using

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29 g

of butane is burnt in excess of

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at STP. Find the volume of the

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of butane is burnt in excess of

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What volume of Butane is burnt for every 1000 cm3 of air used in the reaction under the same conditions.

The correct option is B 30.7 cm3 2C4H10+13O2→8CO2+10H2O Volume of O2 in 1000cm3 of air = 20% =20100×1000=200 cm3 2C4H10+13O2→8CO2+10H2O 2 Vol → 13 Vol ∴ Volume of butane burnt =200×213 =40013 =30.7 cm3

What volume of Butane is burnt for every $1000 c m^{3}$ of air used in the reaction under the same conditions.