Question

What volume of decimolar $KMn{O}_4$ solution will be needed for complete oxidation of $100ml$, semimilar oxalic acid and solution.

Answer 1

${5C}^{(-)}+{MnO}_4^{-}\to {Mn}^{+2}$

$C_2{O}_4^{-2}\to {2CO}_2+2e^{(-)}$

Hence $N_1{V}_1=N_2{V}_2$

$\left(0.1\right)\times V_1\times 5=100\times 2\times 0.5$

$V_1=200ml$ of ${KMnO}_4$.