What volume of hydrogen measured at 27∘C and 776.7 mm pressure would be obtained by treating 0.65 g of pure zinc with sufficient amount of dilute hydrochloric acid? Aq. tension at 27∘C is 26.7 mm; At. mass of Zn is 65.
249.43 ml
The reaction of Zn replacing H2 from H2SO4.
∴ Zn + H2SO4 → H2SO4 + H2
∴ 65g of Zn = 22.4 L of H2 at NTP
0.65g of Zn = 0.224 L of H2 at NTP = 224 ml
Other pressure and temperature are given and volume at that condition is asked.
Thus,use P1V1T1 = P2V2T2
P2=776.7− aqueous tension
⇒ 760×224273 = 750×V2300
⇒ V2 = 249.43 ml