What volume of oxygen would be required for the complete combustion of 100 litres of ethane? The following equation is as follows:
2C2H6+7O2→4CO2+6H2O
350 litres
2C2H6(g)2 vol.+7O2(g)5 vol.→4CO2(g)4 vol.+6H2O(g)6 vol.
By Gay Lussac’s law:
2 vol. of ethane require for complete combustion = 7 vol. of oxygen.
100 litres of ethane will require for complete combustion = 72×100 = 350 litres of oxygen.
Hence, the required volume of oxygen is 350 litres.