Question

What volume of water must be added to 50 mL of a 0.5 M $H_{2}S{O}_4$ to give a solution having a concentration of 0.1 M $H_{2}S{O}_4?$

• A. $200\text{mL}$
• B. $250\text{mL}$
• C. $105\text{mL}$
• D. $550\text{mL}$

Answer 1

The correct option is A $200\text{mL}$

Let’s assume the volume after dilution to be V mL and the concentration becomes 0.1 M.
$M_1{V}_1=M_2{V}_2$
$\Rightarrow (0.1\times V)=(0.5\times 50)$
On solving, V = 250 mL
So, the volume of water to be added = (250-50) mL = 200 mL