What volume of water would be needed to dilute 50mL of a 3M HCl solution to 1M?
When performing a dilution you can use the relationship:
M1V1=M2V2
Where:
M1= Molarity of the original solution
V1= Volume of the original solution
M2= Molarity of the final solution
V2= Volume of the final solution
Substituting:
50×3=1×V2
V2=150ml.
This is the final Volume.
Therefore, you need 100 ml of water to make a final volume of 150 because 50 ml comes from the Original Volume of 3M HCl.