What volume strength of 100 mL H2O2 is required for the complete reaction with 15.8 g of KMnO4 in basic medium? (Molar mass of KMnO4 is 158 g/mol).
The correct option is A 5.6
15.8 g of KMnO4 = 0.1 mol KMnO4
Since n-factor of KMnO4 in basic medium is 1, thus
0.1 mol KMnO4=0.1 eqv. of KMnO4
Therefore, H2O2 required is 0.1 eqv.
So, volume strength =5.6×N