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Question

What volume strength of 100 mL H2O2 is required for the complete reaction with 15.8 g of KMnO4 in basic medium? (Molar mass of KMnO4 is 158 g/mol).


A
5.6
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B
11.2
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C
1.86
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D
3.73
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Solution

The correct option is A 5.6
15.8 g of KMnO4 = 0.1 mol KMnO4
Since n-factor of KMnO4 in basic medium is 1, thus
0.1 mol KMnO4=0.1 eqv. of KMnO4
Therefore, H2O2 required is 0.1 eqv.
So, volume strength =5.6×N
5.6×0.1100×1000=5.6

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