Question

What volume would 16 $g$ of molecular oxygen gas occupy at $STP$?

• A. 5.6 $L$
• B. 11.2 $L$
• C. 22.4 $L$
• D. 33.6 $L$
• E. 44.8 $L$

Answer 1

The correct option is B 11.2 $L$

Total no. of moles of $O_2$$=$$16/32moles$$=$$0.5moles$

Volume of $1mole$ of $O_2$ at $STP$$=$$22.4L$

so volume of $0.5mole$$=$22.4*0.5$=$$11.2L$