What volume would 16 $g$ of molecular oxygen gas occupy at $S T P$ ?

5.6

L

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11.2

L

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22.4

L

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33.6

L

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44.8

L

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Solution

The correct option is B 11.2 $L$
Total no. of moles of $O_{2}$ $=$ $16 / 32 m o l e s$ $=$ $0.5 m o l e s$
Volume of $1 m o l e$ of $O_{2}$ at $S T P$ $=$ $22.4 L$
so volume of $0.5 m o l e$ $=$ 22.4*0.5 $=$ $11.2 L$

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