What was the day of the week on 18th August, 2008?
Monday
18 August, 2008 = (2007 years + period from 1.1.2008 to 18.8.2008)
Odd days in 1600 years = 0
Odd days in 400 years = 0
7 years = (6 ordinary years + 1 leap year) = (6×1+2) odd days
≡ 1 odd day
Jan + Feb + March + April + May + June + July + August
(31 + 29 + 31 + 30 + 31 + 30 + 31 + 18) = 231 days = (33 weeks)≡ 0 odd days
Total number of odd days = (0+0+1+0) =1≡ 1 odd day
Given day is Monday.