What weight of AgCl in grams will be precpitated when a solution containing 2.925gNaCl is added to a solution of 5.1g of AgNO3 (Given : Molecular Mass of NaCl=58.5andAgNO3=170 (Give your answer upto two decimal only)
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Solution
AgNO3+NaCl→AgCl+NaNO3m moles. mixed5.1170×10002.92558.5×1000=30=50m moles. left047.603030m moles of AgCl formed = 30w143.5×1000=30WAgCl=4.305g