What weight of CaCO3 must be decomposed to produce a sufficient quantity of carbon dioxide to convert 21.2g of Na2CO3 completely into NaHCO3. (Molar mass of Na=23g/mol,Ca=40g/mol): CaCO3→CaO+CO2Na2CO3+CO2+H2O→2NaHCO3
A
100g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
120g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B20g CaCO3→CaO+CO2 Na2CO3+CO2+H2O→2NaHCO3
Mol of Na2CO3=21.2106=0.2mol
1 mol of Na2CO3 reacts with 1 mol of CO2 and 1 mol of CO2 is produced from 1 mol of CaCO3 i.e. mol of Na2CO3=mol of CO2=mol of CaCO3
So, 0.2 mol of Na2CO3 reacts with 0.2 mol of CO2 which means 0.2 mol of CO2 is produced from 0.2 mol of CaCO3. weight of CaCO3 formed = Moles × Molar mass hence, weight of CaCO3=0.2mol×100g/mol=20g