Question

What will be the apparent weight of a body of mass 'M' in a lift, moving up with a constant acceleration 'g'? [consider g as acceleration due to gravity]

• A.
  $Mg$
• B.
  $Zero$
• C.
  $2Mg$
• D.
  $\frac{Mg}{2}$

Answer 1

The correct option is C

$2Mg$
Acceleration of elevator, a = g

Mass of the body = M

Let R be the apparent weight.

$\therefore R–Mg=Ma\Rightarrow R=Mg+Ma\Rightarrow R=Mg+Mg(\because a=g)\Rightarrow R=2Mg$

Hence, the correct answer is option (c).