What will be the effect of addition of a catalyst at constant temperature?

The equilibrium constant will remain constant

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Δ H

of the reaction will remain constant

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k_{f}

and

k_{b}

will increase by the same extent

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Equilibrium composition will change

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Solution

The correct option is C $k_{f}$ and $k_{b}$ will increase by the same extent
The equilibrium constant will remain constant
$K = \frac{k_{f}}{k_{b}}$
$k_{f}$ and $k_{b}$ will increase by the same extent because the activation energy increases or decreases by the same extent on the addition of the catalyst. As a result, the equlibrium constant and also
$Δ H$ = $E_{a} (f) - E_{b} (b)$
$Δ H$ of the reaction will remain constant.

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