What will be the HCF of 2- 3- 7- 9 -2- 3- 9- 11 and 2- 3- 4- 5-

Given factors, (2× 3× 7× 9) #160; ,(2× 3× 9× 11) #160; ,(2× 3× 4× 5) Therefore,Required #160; HCF= Product of common prime factors havi ...

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Standard VI

Mathematics

Factors

What will be ...

Question

What will be the $H C F$ of $(2 \times 3 \times 7 \times 9)$ $, (2 \times 3 \times 9 \times 11)$ and $(2 \times 3 \times 4 \times 5) ?$

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Solution

Given factors,
$(2 \times 3 \times 7 \times 9)$ $, (2 \times 3 \times 9 \times 11)$ $, (2 \times 3 \times 4 \times 5)$

Therefore,
Required $H C F =$ Product of common prime factors having least powers
$= 2 \times 3 = 6$

Hence, this is the answer.

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Similar questions

Q. What should be added to

6 a^{3} + 5 a - 2 a^{2} - 7

to get

9 a^{2} - 2 a - a^{3} + 2

$(i) \frac{3}{7} + \frac{- 4}{9} - \frac{- 11}{7} - \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} - \frac{1}{3} - \frac{2}{5} (i i i) \frac{4}{7} - \frac{- 8}{9} - \frac{- 13}{7} + \frac{17}{9}$

Find the product:

(i) (ii) (iii)

(iv) (v) (vi)

Q. Simplify:

\frac{5}{3} + \frac{11}{2} + \frac{- 9}{4} + \frac{- 8}{3} + \frac{- 7}{2}

Fill in the blanks:

$(i) - 4 \times \frac{7}{9} = \frac{7}{9} \times$ ___

$(i i) \frac{5}{11} \times \frac{- 3}{8} = \frac{- 3}{8} \times$ ___

$(i i i) \frac{1}{2} \times (\frac{3}{4} + \frac{- 5}{12}) = \frac{1}{2} \times$ ____ $+ (\times) \frac{- 5}{12}$

$(i v) \frac{- 4}{5} \times \frac{5}{7} \times$ ___ $= (\frac{- 4}{5} \times \frac{5}{7}) \times \frac{- 8}{9}$

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What will be the HCF of (2×3×7×9) ,(2×3×9×11) and (2×3×4×5)?

Given factors,(2×3×7×9) ,(2×3×9×11) ,(2×3×4×5)Therefore,Required HCF= Product of common prime factors having least powers =2×3=6Hence, this is the answer.

What will be the $H C F$ of $(2 \times 3 \times 7 \times 9)$ $, (2 \times 3 \times 9 \times 11)$ and $(2 \times 3 \times 4 \times 5) ?$

Given factors,
$(2 \times 3 \times 7 \times 9)$ $, (2 \times 3 \times 9 \times 11)$ $, (2 \times 3 \times 4 \times 5)$

Therefore,
Required $H C F =$ Product of common prime factors having least powers
$= 2 \times 3 = 6$

Hence, this is the answer.