What will be the heat reaction for the following reaction? Will the reaction be exothermic or endothermic?
$F e_{2} O_{3 (s)} + 3 H_{2} O_{(l)}$
$△ \int H^{0} (H_{2} O, I)$ = $- 285.83 k J m o l^{- 1}$
$△ \int H^{0} (F e_{2} O_{3}, S)$ = $- 824.2 k J m o l^{- 1}$

- 824.2 k J m o l^{- 1}

, exothermic

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+ 33.3 k J m o l^{- 1}

, endothermic

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- 33.3 k J m o l^{- 1}

, exothermic

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+ 824.2 k J m o l^{- 1}

, endothermic

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Solution

The correct option is D $- 33.3 k J m o l^{- 1}$ , exothermic
$Δ_{f} H^{0} (F e_{(s)}) = 0$ , $Δ_{f} H^{0} (H_{2 (g)}) = 0$
$Δ_{r} H^{0}$ = 3(-285.83) - (-824.2) = -33.3 kJ $m o l^{- 1}$
Reaction is exothermic.

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What will be the heat reaction for the following reaction? Will the reaction be exothermic or endothermic?Fe2O3(s)+3H2O(l)△∫H0(H2O,I) =−285.83kJmol−1△∫H0(Fe2O3,S) = −824.2kJmol−1

The correct option is D −33.3kJmol−1, exothermicΔfH0(Fe(s))=0, ΔfH0(H2(g))=0ΔrH0 = 3(-285.83) - (-824.2) = -33.3 kJ mol−1Reaction is exothermic.

What will be the heat reaction for the following reaction? Will the reaction be exothermic or endothermic?
$F e_{2} O_{3 (s)} + 3 H_{2} O_{(l)}$
$△ \int H^{0} (H_{2} O, I)$ = $- 285.83 k J m o l^{- 1}$
$△ \int H^{0} (F e_{2} O_{3}, S)$ = $- 824.2 k J m o l^{- 1}$

The correct option is D $- 33.3 k J m o l^{- 1}$ , exothermic
$Δ_{f} H^{0} (F e_{(s)}) = 0$ , $Δ_{f} H^{0} (H_{2 (g)}) = 0$
$Δ_{r} H^{0}$ = 3(-285.83) - (-824.2) = -33.3 kJ $m o l^{- 1}$
Reaction is exothermic.