What will be the magnitude of torque on an electric dipole having dipole moment of 4- 10 -9 cm placed in a uniform electric field of intensity of 5- 10 4 N C -1 making an angle 180o with the field-

The correct option is C 0 (zero) τ #160; = p × E τ⟶ torque [θ⟶ angle of the dipole moment (p) with the field (E)] ∴ |τ |=pEs ...

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Byju's Answer

Standard XII

Physics

Electric Field Due to a Dipole

What will be ...

Question

What will be the magnitude of torque on an electric dipole having dipole moment of $4 \times 10^{- 9} c m$ placed in a uniform electric field of intensity of $5 \times 10^{4} N C^{- 1}$ making an angle $180^{o}$ with the field.

10^{- 4} N - m

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2 \times 10^{- 4} N - m

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0

(zero)

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10^{- 6} N - m

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Solution

The correct option is C $0$ (zero)
$\to τ = \to p \times \to E$
$\to τ ⟶$ torque
$[θ ⟶$ angle of the dipole moment $(p)$ with the field $(E)]$
$∴ | τ | = p E sin θ = p E sin 180 ° = 0$

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What will be the magnitude of torque on an electric dipole having dipole moment of 4×10−9cm placed in a uniform electric field of intensity of 5×104NC−1 making an angle 180o with the field.

The correct option is C 0 (zero)→τ=→p×→E→τ⟶torque[θ⟶angle of the dipole moment(p) with the field(E)]∴|τ|=pEsinθ=pEsin180°=0

What will be the magnitude of torque on an electric dipole having dipole moment of $4 \times 10^{- 9} c m$ placed in a uniform electric field of intensity of $5 \times 10^{4} N C^{- 1}$ making an angle $180^{o}$ with the field.

The correct option is C $0$ (zero)
$\to τ = \to p \times \to E$
$\to τ ⟶$ torque
$[θ ⟶$ angle of the dipole moment $(p)$ with the field $(E)]$
$∴ | τ | = p E sin θ = p E sin 180 ° = 0$