What will be the mass of $224 c m^{3}$ of nitrogen( $N_{2}$ ) gas at STP

0.82 g

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0.28 g

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8.26 g

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4.28 g

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Solution

The correct option is D $0.28 g$
Unit conversion : $1 c m^{3} = 0.001 l i t r e$
$\Rightarrow 224 c m^{3} = 0.224 l i t r e s$
At STP, a mole of a gas occupies 22.4 litres of volume.
One mole of nitrogen $N_{2}$ is $14 \times 2 = 28 g$
$\Rightarrow$ The mass of 22.4 litres of $N_{2}$ is 28g
Then, the mass of 0.224 litres of $N_{2}$ is
$\frac{28}{22.4} \times 0.224 = 0.28 g$
$∴$ Mass of 0.224 litres of $N_{2}$ gas at STP is 0.28 g

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What will be the mass of 224cm3 of nitrogen(N2) gas at STP

What will be the mass of $224 c m^{3}$ of nitrogen( $N_{2}$ ) gas at STP