What will be the minimum pressure required to compress $500 d m^{3}$ of air at 1 bar to $200 d m^{3}$ at $30^{o} C$ ?

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Solution

$P_{1} V_{1} = P_{2} V_{2}$ (at constant T)
$P_{2} = \frac{P_{1} V_{1}}{V_{2}} = \frac{(1 b a r) \times (500 d m^{3})}{(200 d m^{3})}$
$= 2.5 b a r .$

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