What will be the molarity of the solutoin containing 18.25 g of HCl gas in 500 g of water ?

(a) 0.1 m (b) 1 M (c) 0.5 m (d) 1 m

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Solution

(d)

Molarity is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.

Thus, $M o l a r i t y (m) = \frac{M o l e s o f s o l u t e}{M a s s o f s o l v e n t (i n k g)}$ ...(i)

Given that, Mass of solvent $(H_{2} O) = 500 g = 0.5 k g$

Weight of HCl = 18.25 g

Molecular weight of HCl $= 1 \times 1 + 1 \times 35.5 = 36.5 g$

Moles of HCl $= \frac{18.25}{36.5} = 0.5$

$m = \frac{0.5}{0.5} = 1 m$ [from Eq. (i)]

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