What will be the overall n-factor for the given disproportionation reaction:
$2 C u B r (a q) \to C u B r_{2} (a q) + C u (s)$

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Solution

For the given reaction :
$2 + 1 C u B r (s) ⟶ + 2 C u B r_{2} (a q) + 0 C u (s)$
Oxidation :
$+ 1 C u ⟶ + 2 C u^{2 +}$
$n_{f} = n_{1} = | 1 - (2) | \times 1 = 1$
Reduction :
$+ 1 C u ⟶ 0 C u$
$n_{f} = n_{2} = | 1 - (0) | \times 1 = 1$
$n_{f} = \frac{n_{1} \times n_{2}}{n_{1} + n_{2}}$
$n_{f} = \frac{1 \times 1}{1 + 1} = 0.5$

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