Question

What will be the pressure in pascal due to a mercury column of $76$cm. Density of mercury is $13.6$ g$c{m}^2$, $g=980$ cm$s^2$?

• A. $1.0129\times {10}^5$Pa
• B. $1.0129\times {10}^4$Pa
• C. $1.0129\times {10}^3$Pa
• D. $1.0129\times {10}^2$Pa

Answer 1

The correct option is A $1.0129\times {10}^5$Pa

h$=76cm$

Pressure=?

Formula to be used : $P=hgd$

Where h = height of mercury column and

d= density of mercury$=13.6gm/cc$

acceleration due to gravity$=980cm/s²$

$P=hgd=13.6\times 980\times 76=1012928dyne.cm²$