What will be the product of $p^{2} - 2 p q$ and $q^{2} + 5 p q$ ?

p q (4 p^{2} - 3 q^{2} + 11 p q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p q (4 p^{2} + 3 q^{2} + 11 p q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p q (4 p^{2} - 3 q^{2} - 11 p q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p q (5 p^{2} - 2 q^{2} - 9 p q)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $p q (5 p^{2} - 2 q^{2} - 9 p q)$
$(p^{2} - 2 p q) \times (q^{2} + 5 p q)$

$= p^{2} (q^{2} + 5 p q) - 2 p q (q^{2} + 5 p q)$

$= p^{2} q^{2} + 5 p^{3} q - 2 p q^{3} - 10 p^{2} q^{2}$

$= 5 p^{3} q - 2 p q^{3} + (p^{2} q^{2} - 10 p^{2} q^{2})$

$= 5 p^{3} q - 2 p q^{3} - 9 p^{2} q^{2}$

$= p q (5 p^{2} - 2 q^{2} - 9 p q)$

Suggest Corrections

Similar questions

p^{2} - 5 p q - q^{2}

- 3 p^{2} + 2 p q - 2 p^{2}

p^{2} - 2 p q + q^{2}

p^{2} + 2 p q - q^{2}

p^{2} + q^{2} + 2 p q

(p^{2} - 2 p q + q^{2}) - r^{2}

(p^{2} - q^{2}) = 2 (p q - q^{2})

Join BYJU'S Learning Program