Question

What will be the quotient and remainder if $y^2+10y+24÷(y+4)$?

• A. Quotient = $(y^2+6)$
  Remainder = $14$
• B. Remainder= $(y+6)$
  Quotient= $0$
• C. Remainder= $(y+6)$
  Quotient= $12$
• D. Quotient = $(y+6)$
  Remainder = $0$

Answer 1

The correct option is D Quotient = $(y+6)$

Remainder = $0$
Given : $(y^2+10y+24)÷(y+4)$
$\begin{array}{c}y+6\\ y+4y^2+10y+24\\ \underset{–}{y^2+4y--}2\\ 6y+24\\ \underset{–}{6y+24--}\\ \underset{–}{0}\end{array}$

Quotient = $(y+6)$
Remainder = $0$