What will be the ratio of the distances moved by a freely falling body from rest in 4th and 5th seconds of journey

4 : 5

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7 : 9

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16 : 25

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1 : 1

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Solution

The correct option is B $7 : 9$
$\frac{D i s t a n c e m o v e d i n 4 t h s e c o n d}{D i s t a n c e m o v e d i n 5 t h s e c o n d}$

$\frac{s_{4} - s_{3}}{s_{5} - s_{4}}$
where, $s = \frac{1}{2} g t^{2}$
So, required ratio
$= \frac{4^{2} - 3^{2}}{5^{2} - 4^{2}} = \frac{7}{9}$

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