What will be the value of the equivalent weight of KBrO3 in the following ionic equation? 2BrO−3+12H++10e−→Br2+6H2O
(Given: The molecular weight of KBrO3 is M.)
A
M4
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B
M6
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C
M10
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D
M5
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Solution
The correct option is DM5 2BrO−3+12H++10e−→Br2+6H2O EKBrO3=molecular weightnumber of electrons gained=2BrO−310⇒BrO−35=KBrO35=M5
Where M stands for molecular weight of KBrO3.