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Question

What will be the volume of 0.1 M H2SO4​ solution required to neutralize 40 mL of 0.1 M KOH solution ?

A
40 mL
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B
39 mL
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C
20 mL
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D
10 mL
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Solution

The correct option is C 20 mL
H2SO4 is dibasic.
n-factor for H2SO4=2
n-factor for KOH=1

The condition of neutralization is :
Equivalents of H2SO4= Equivalents of KOH
NH2SO4×VH2SO4=NKOH×VKOH

Normality=Molarity×nf

MH2SO4×nfH2SO4×VH2SO4=MKOH×nfKOH×VKOH

Putting the values,

0.1×2×VH2SO4=0.1×1×40
VH2SO4=20 mL

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