Question

What will be the volume of $2.8g$ of carbon monoxide at ${27}^{\circ }C$ and $0.821$ atmospheric pressure?

• A. $2.5L$
• B. $4L$
• C. $3.5L$
• D. $3L$

Answer 1

Answer: (D)

$3L$

Given, $m=2.8g$, $T={27}^{\circ }C=300K$, and $P=0.821atm$

$n=\frac{m}{M}=\frac{2.8}{28}=0.1$

By Ideal gas equation;

$PV=nRT$
$\therefore V=\frac{nRT}{P}=\frac{0.1\times 0.0821\times 300}{0.821}=3L$.