Question

The volume of 2.8 g of carbon monoxide at ${27}^{\circ }C$ and $0.821$ atm pressure is $(R=0.0821lit.atmmo{l}^{–1}{K}^{–1})$

• A. $30L$
• B. $3L$
  
• C. $0.3L$
• D. $1.5L$

Answer 1

The correct option is B $3L$


$CO=28un=\frac{2.8}{28}=0.1molV=\frac{nRT}{P}=\frac{0.1\times 0.0821\times 300}{0.821}V=3L$