The volume of 2.8 g of $C O$ at $27^{0} C$ and 0.821 atm pressure is:

1.5 litre

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3 litre

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30 litre

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0.3 litre

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Solution

The correct option is B 3 litre
Molecular mass of $C O$ = 28.
Moles of $C O$ present $= \frac{2.8}{28}$
$V = \frac{n R T}{P} = \frac{\frac{2.8}{28} \times 0.0821 \times 300}{0.821} = 3 l i t r e s$

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