What will be the volume of 3.2 gram atoms of oxygen gas at STP?

2.24 lit

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0.0224 lit

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0.224 lit

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22.4 lit

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Solution

The correct option is A 2.24 lit
Number of moles = $\frac{v o l u m e o f g a s}{22.4 l i t r e s} v o l u m e o f g a s = n u m b e r o f m o l e s \times 22.4 n u m b e r o f m o l e s = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{3.2}{32} = 0.1 m o l e s V o l u m e o f g a s = 0.1 \times 22.4 \times = 2.24 l i t r e s$

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