What will be the weight of CO having the same number of oxygen atoms as present in 22 g of $C O_{2}$ ?

28 g

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22 g

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44 g

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72 g

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Solution

The correct option is B 28 g
1 mol of $C O_{2} = 12 + 32 = 44 g$

Number of oxygen in 1 molecule of $C O_{2} = 2$

Therefore, 44 g $C O_{2}$ contains 2 moles of oxygen

22 g $C O_{2}$ contains $= \frac{2}{44} \times 22 = 1$ mole oxygen atom

1 mole of $C O = 12 + 16 = 28 g$

$∴$ 28 g $C O$ contains 1 mol oxygen atom.

The equal number of moles means an equal number of atoms of oxygen.
Hence, the correct option is $A$

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