wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What would be an appropriate unit for the rate constant of a second-order reaction?

A
s1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
molL1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
molL1s1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Lmol1s1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
E
mol2L2s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D Lmol1s1
The equation for the rate of a second-order reaction is calculated as follows:

Rate = k[A]2, where k is the rate constant of the reaction and [A] is the concentration of the reactant at any instant. It is raised to the power of 2, because, it is a second-order reaction.

Unit for Rate is conctime that is molL1s1. We need to find the unit of k. Unit of [A]2 is (conc)2 that is mol2L2.

Putting all these in the equation, we have,

molL1s1 = (k) mol2L2

Thus k = Lmol1s1

Option D is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Order and Molecularity of Reaction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon