Question

What would be the heat released when $0.5$ mol of HCl is neutralised with $0.5$ mol of NaOH?

• A. $\Delta H=-28.55kJ$
• B. $\Delta H=+28.55kJ$
• C. $\Delta H=-26.55kJ$
• D. $\Delta H=+26.5kJ$

Answer 1

The correct option is A $\Delta H=-28.55kJ$

As we know,

Amount of heat released when one mole of strong acid reacts with one mole of the strong base $=-57.1KJ$

$0.5HCl+0.5NaOH⟶0.5NaCl+0.5H_{2}O$

Amount of heat released $=\frac{-57.1}{2}=-28.55kJ$