What would be the length of a polypeptide translated from mRNA which is encoded by 2988bp of a bacterial gene?
A
989
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B
992
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C
995
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D
998
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Solution
The correct option is C995 Each base pair codes for a nucleotide of mRNA hence mRNA from this bacterial gene will consist of 2988 nucleotides. As three-nucleotide sequence ( triplet codon ) codes for an amino acid in a polypeptide, polypeptide translated from this gene should have 2988/3 = 996 amino acids. Though, last codon (stop codon ) do not code for any amino acid hence the actual number of amino acids are 995.