CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What would be the length of a polypeptide translated from mRNA which is encoded by 2988bp of a bacterial gene?

A
989
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
992
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
995
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
998
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 995
Each base pair codes for a nucleotide of mRNA hence mRNA from this bacterial gene will consist of 2988 nucleotides. As three-nucleotide sequence ( triplet codon ) codes for an amino acid in a polypeptide, polypeptide translated from this gene should have 2988/3 = 996 amino acids. Though, last codon (stop codon ) do not code for any amino acid hence the actual number of amino acids are 995.
So, the correct option is '995'.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
RNA
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon